If i=1∑9(xi−5)=9andi=1∑9(xi−5)2=45 then the standard deviation of the 9 items x1,x2,…..,x9 is

Name: Video solution 1: If i=1∑9(xi−5)=9andi=1∑9(xi−5)2=45 then the standard deviation of the 9 items x1,x2,…..,x9 is
Uploaded: 2021-01-01T18:41:02.000Z
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Description: Video solution 1: If i=1∑9(xi−5)=9andi=1∑9(xi−5)2=45 then the standard deviation of the 9 items x1,x2,…..,x9 is

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If {_{{{i}={1}}}^{{9}}}{({x}_{{i}}-{5})}={9}{{and}}{_{{{i}={1}

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If $i = 1 \sum 9 (x_{i} - 5) = 9 and i = 1 \sum 9 (x_{i} - 5)^{2} = 45$ then the standard deviation of the 9 items $x_{1}, x_{2}, \dots .., x_{9}$ is

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i = 1 \sum 9 (x_{i} - 5) = 9 and i = 1 \sum 9 (x_{i} - 5)^{2} = 45

then the standard deviation of the 9 items

x_{1}, x_{2}, \dots .., x_{9}

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Question Text	If $i = 1 \sum 9 (x_{i} - 5) = 9 and i = 1 \sum 9 (x_{i} - 5)^{2} = 45$ then the standard deviation of the 9 items $x_{1}, x_{2}, \dots .., x_{9}$ is
Answer Type	Video solution: 1
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If i=1∑9​(xi​−5)=9andi=1∑9​(xi​−5)2=45 then the standard deviation of the 9 items x1​,x2​,…..,x9​ is

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If $i = 1 \sum 9 (x_{i} - 5) = 9 and i = 1 \sum 9 (x_{i} - 5)^{2} = 45$ then the standard deviation of the 9 items $x_{1}, x_{2}, \dots .., x_{9}$ is