If sin−1x+sin−1y=32π then (cos−1x+cos−1y)= ?

As we know sin−1x+cos−1x=2πthen,sin−1x+sin−1y=32π⇒(2π−cos−1x)+(2π−cos−1y)=32π.∴cos−1x+cos−1y=(π−32π)=3π.

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If ^{-1}x+^{-1}y= {2}{3} then (^{-1}x+^{-1}y)= ?

Question

If $sin^{- 1} x + sin^{- 1} y = \frac{2 π}{3}$ then $(cos^{- 1} x + cos^{- 1} y) =$ ?

\frac{π}{6}

\frac{π}{3}

π

\frac{2 π}{3}

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Jack Discussed

sin^{- 1} x + sin^{- 1} y = \frac{2 π}{3}

then

(cos^{- 1} x + cos^{- 1} y) =

15 mins ago

Discuss this question LIVE

15 mins ago

As we know

sin^{- 1} x + cos^{- 1} x = \frac{π}{2}

then,

sin^{- 1} x + sin^{- 1} y = \frac{2 π}{3}

\Rightarrow (\frac{π}{2} - cos^{- 1} x) + (\frac{π}{2} - cos^{- 1} y) = \frac{2 π}{3} .

∴ cos^{- 1} x + cos^{- 1} y = (π - \frac{2 π}{3}) = \frac{π}{3} .

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Question Text	If $sin^{- 1} x + sin^{- 1} y = \frac{2 π}{3}$ then $(cos^{- 1} x + cos^{- 1} y) =$ ?
Answer Type	Text solution:1
Upvotes	150