If $r^{t h}$ and $(r + 1)^{t h}$ terms in the expansion of $(p + q)^{n}$ are equal, then $\frac{( n + 1 ) q}{r ( p + q )}$ is

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Michael Discussed

r^{t h}

and

(r + 1)^{t h}

terms in the expansion of

(p + q)^{n}

are equal, then

\frac{( n + 1 ) q}{r ( p + q )}

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Question Text

r^{t h}

and

(r + 1)^{t h}

terms in the expansion of

(p + q)^{n}

are equal, then

\frac{( n + 1 ) q}{r ( p + q )}

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