If $R=\frac{{\left[1+{\left(\frac{dy}{dx}\right)}^2\right]}^{3/2}}{\frac{d^{2}y}{dx2}}$ , then$R^{2/3}$ can be put in the form of $\frac{1}{{\left(\frac{d^{2}y}{{dx}^2}\right)}^{2/3}}+\frac{1}{{\left(\frac{d^{2}x}{{dy}^2}\right)}^{2/3}}$ b. $\frac{1}{{\left(\frac{d^{2}y}{{dx}^2}\right)}^{2/3}}-\frac{1}{{\left(\frac{d^{2}x}{{dy}^2}\right)}^{2/3}}$ c. $\frac{2}{{\left(\frac{d^{2}y}{{dx}^2}\right)}^{2/3}}+\frac{2}{{\left(\frac{d^{2}x}{{dy}^2}\right)}^{2/3}}$ d. $\frac{1}{{\left(\frac{d^{2}y}{{dx}^2}\right)}^{2/3}}\frac{\dot{1}}{{\left(\frac{d^{2}x}{{dy}^2}\right)}^{2/3}}$

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