If one of the diameters of the circle, given by the equation, $x^{2} + y^{2} - 4 x + 6 y - 12 = 0$ , is a chord of a circle S, whose centre is at $(- 3, 2)$ , then the radius of S is :

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If one of the diameters of the circle, given by the equation,

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

, is a chord of a circle S, whose centre is at

(- 3, 2)

, then the radius of S is :

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Question Text

If one of the diameters of the circle, given by the equation,

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

, is a chord of a circle S, whose centre is at

(- 3, 2)

, then the radius of S is :

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