If $^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}$ then the value of $n + r$ is.

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Samuel Discussed

^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}

then the value of

n + r

is.

9 mins ago

Discuss this question LIVE

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Question Text

^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}

then the value of

n + r

is.

Filo tutor solution