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If = ( e ^ { y } - x ) ^ { - 1 } , where y ( 0 ) = 0 , then y

Question

If $= (e^{y} - x)^{- 1},$ where $y (0) = 0,$ then $y$ is expressed explicitly $a s$

\frac{1}{2} ln (1 + x^{2})

ln (1 + x^{2})

ln (x + 1 + x^{2})

ln (x + 1 - x^{2})

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Henry Discussed

= (e^{y} - x)^{- 1},

where

y (0) = 0,

then

y

is expressed explicitly

a s

9 mins ago

Discuss this question LIVE

9 mins ago

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Question Text

= (e^{y} - x)^{- 1},

where

y (0) = 0,

then

y

is expressed explicitly

a s

Filo tutor solution