If $(a_{1} + i b_{1}) (a_{2} + i b_{2}) ....... (a_{n} + i b_{n}) = A + i B$ then $(a_{1}^{2} + i b_{1}^{2}) (a_{2}^{2} + i b_{2}^{2}) ....... (a_{n}^{2} + i b_{n}^{2}) =$

A^{2} + B^{2}

A^{2} - B^{2}

A^{3} + B^{3}

A^{3} - B^{3}

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Elijah Discussed

(a_{1} + i b_{1}) (a_{2} + i b_{2}) ....... (a_{n} + i b_{n}) = A + i B

then

(a_{1}^{2} + i b_{1}^{2}) (a_{2}^{2} + i b_{2}^{2}) ....... (a_{n}^{2} + i b_{n}^{2}) =

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Question Text

(a_{1} + i b_{1}) (a_{2} + i b_{2}) ....... (a_{n} + i b_{n}) = A + i B

then

(a_{1}^{2} + i b_{1}^{2}) (a_{2}^{2} + i b_{2}^{2}) ....... (a_{n}^{2} + i b_{n}^{2}) =

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