If (1+xn)=C0+C1+C2x2++Cnxn, then the value of C02+2C12+3C22++n+1Cn2 is equal to

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If ( {1+x}^{n} )={C}_{0}+{C}_{1}+{C}_{2}{x}^{2}++{C}_{n}{x}^{n

Question

If $(1 + x^{n}) = C_{0} + C_{1} + C_{2} x^{2} + + C_{n} x^{n}$ , then the value of $C_{0}^{2} + \frac{C _{1}^{2}}{2} + \frac{C _{2}^{2}}{3} + + \frac{C _{n}^{2}}{n + 1}$ is equal to

\frac{( 2 n - 1 ) !}{{ ( n + 1 ) ! } ^{2}}

\frac{( 2 n - 1 ) !}{( n + 1 ) !}

\frac{( 2 n + 1 ) !}{{ ( n + 1 ) ! } ^{2}}

\frac{( 2 n ) !}{( n + 1 ) !}

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Henry Discussed

(1 + x^{n}) = C_{0} + C_{1} + C_{2} x^{2} + + C_{n} x^{n}

, then the value of

C_{0}^{2} + \frac{C _{1}^{2}}{2} + \frac{C _{2}^{2}}{3} + + \frac{C _{n}^{2}}{n + 1}

is equal to

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Question Text	If $(1 + x^{n}) = C_{0} + C_{1} + C_{2} x^{2} + + C_{n} x^{n}$ , then the value of $C_{0}^{2} + \frac{C _{1}^{2}}{2} + \frac{C _{2}^{2}}{3} + + \frac{C _{n}^{2}}{n + 1}$ is equal to
Answer Type	Video solution: 1
Upvotes	150