If inverse of A=⎣⎡1211−1−11−11⎦⎤ is 6−1⎣⎡−2−3−1−2020α −3⎦⎤ then α=

Question

If inverse of A=⎣⎡​121​1−1−1​1−11​⎦⎤​ is 6−1​⎣⎡​−2−3−1​−202​0α −3​⎦⎤​ then α=

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Given,A=⎣⎡​121​1−1−1​1−11​⎦⎤​A−1=⎣⎡​121​1−1−1​1−11​⎦⎤​−1=⎣⎡​121​1−1−1​1−11​∣∣∣​100​010​001​⎦⎤​R1​↔R2​=⎣⎡​211​−11−1​−111​∣∣∣​010​100​001​⎦⎤​R2​←R2​−21​⋅R1​R3​←R3​−21​⋅R1​=⎣⎡​200​−123​−21​​−123​23​​∣∣∣​010​1−21​−21​​001​⎦⎤​R3​←R3​+31​⋅R2​=⎣⎡​200​−123​0​−123​2​∣∣∣​0131​​1−21​−32​​001​⎦⎤​R3​←21​⋅R3​R2​←R2​−23​⋅R3​=⎣⎡​200​−123​0​−101​∣∣∣​043​61​​10−31​​0−43​21​​⎦⎤​R1​←R1​+1⋅R3​R2​←32​⋅R2​=⎣⎡​200​−110​001​∣∣∣​61​21​61​​32​0−31​​21​−21​21​​⎦⎤​R1​←R1​+1⋅R2​=⎣⎡​200​010​001​∣∣∣​32​21​61​​32​0−31​​0−21​21​​⎦⎤​R1​←21​⋅R1​=⎣⎡​100​010​001​∣∣∣​31​21​61​​31​0−31​​0−21​21​​⎦⎤​=⎣⎡​31​21​61​​31​0−31​​0−21​21​​⎦⎤​=−61​⎣⎡​−2 −3 −1​−2 02​03−3​⎦⎤​∴α=3

Question Text	If inverse of $A = ⎣ ⎡ 121 1 - 1 - 1 1 - 1 1 ⎦ ⎤$ is $\frac{- 1}{6} ⎣ ⎡ - 2 - 3 - 1 - 2 02 0 α - 3 ⎦ ⎤$ then $α =$
Answer Type	Text solution:1
Upvotes	150

If inverse of $A = ⎣ ⎡ 121 1 - 1 - 1 1 - 1 1 ⎦ ⎤$ is $\frac{- 1}{6} ⎣ ⎡ - 2 - 3 - 1 - 2 02 0 α - 3 ⎦ ⎤$ then $α =$

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If inverse of A=⎣⎡​121​1−1−1​1−11​⎦⎤​ is 6−1​⎣⎡​−2−3−1​−202​0α −3​⎦⎤​ then α=

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Practice questions from similar books

If inverse of $A = ⎣ ⎡ 121 1 - 1 - 1 1 - 1 1 ⎦ ⎤$ is $\frac{- 1}{6} ⎣ ⎡ - 2 - 3 - 1 - 2 02 0 α - 3 ⎦ ⎤$ then $α =$