If \displaystyle\int\ {x}^{{5}}\ {e}^{{-{4}{x}^{{3}}}}{\left.{d}{x}\right.}=

\int x^{5} e^{- 4 x^{3}} d x = \frac{1}{48} e^{- 4 x^{3}} (f (x)) + c

, where

c

is constant of intergration then

f (x)

equals to (a)

- 4 x^{3} - 1

(b)

- 1 - 2 x^{3}

(c)

4 x^{3} + 1

(d)

1 - 2 x^{3}

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Question Text

If \displaystyle\int\ {x}^{{5}}\ {e}^{{-{4}{x}^{{3}}}}{\left.{d}{x}\right.}=

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