If 32,k,85k are in A.P. then k=

Given 32,k,85k are in AP⟹2k=32+85k⟹2k−85k=32⟹811k=32⟹k=3316

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If {2}{3}, {k}, {5 k}{8} are in A.P. then {k}=

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If $\frac{2}{3}, k, \frac{5 k}{8}$ are in A.P. then $k =$

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Theodore Discussed

\frac{2}{3}, k, \frac{5 k}{8}

are in A.P. then

k =

6 mins ago

Discuss this question LIVE

6 mins ago

Given

\frac{2}{3}, k, \frac{5 k}{8}

are in

A P

⟹ 2 k = \frac{2}{3} + \frac{5 k}{8}

⟹ 2 k - \frac{5 k}{8} = \frac{2}{3}

⟹ \frac{11 k}{8} = \frac{2}{3}

⟹ k = \frac{16}{33}

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