If f(x)∣∣xncosxsinxn!cos2nπsin(2nπ)248∣∣, then find the value of dxndn[f(x)]x=0

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Question

$If f (x) ∣ ∣ x^{n} cos x sin x n! cos \frac{n π}{2} sin (\frac{n π}{2}) 248 ∣ ∣, then find the value$
$o f \frac{d ^{n}}{d x ^{n}} [f (x)]_{x = 0}$

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If f (x) ∣ ∣ x^{n} cos x sin x n! cos \frac{n π}{2} sin (\frac{n π}{2}) 248 ∣ ∣, then find the value

o f \frac{d ^{n}}{d x ^{n}} [f (x)]_{x = 0}

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Question Text

If f (x) ∣ ∣ x^{n} cos x sin x n! cos \frac{n π}{2} sin (\frac{n π}{2}) 248 ∣ ∣, then find the value

o f \frac{d ^{n}}{d x ^{n}} [f (x)]_{x = 0}