If f(x) =x+7 and g(x)=x−7, x∈R, find (fog)(7). function f:R→R defined by f(x)=23x+5 is an invertible function, find f−1

f(x)=x+7g(x)=x−7,x∈Rfog(x)=f(x−7)(x)=(x−7+7)(x)=xfog(7)=7f(x)=23x+5y=23x+5Swapping x=23y+52x=3y+52x−5=3yy=32x−5f−1(x)=32x−5

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If f(x) = x+7 and g(x) = x-7, x R , find (fog)(7). function

Question

If $f (x) = x + 7$ and $g (x) = x - 7$ , $x \in R$ , find $(f o g) (7)$ . function $f : R \to R$ defined by $f (x) = \frac{3 x + 5}{2}$ is an invertible function, find $f^{- 1}$

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Harper Discussed

f (x) = x + 7

and

g (x) = x - 7

x \in R

, find

(f o g) (7)

. function

f : R \to R

defined by

f (x) = \frac{3 x + 5}{2}

is an invertible function, find

f^{- 1}

12 mins ago

Discuss this question LIVE

12 mins ago

f (x) = x + 7

g (x) = x - 7, x \in R

f o g (x) = f (x - 7) (x)

= (x - 7 + 7) (x)

= x

f o g (7) = 7

f (x) = \frac{3 x + 5}{2}

y = \frac{3 x + 5}{2}

Swapping

x = \frac{3 y + 5}{2}

2 x = 3 y + 5

2 x - 5 = 3 y

y = \frac{2 x - 5}{3}

f^{- 1} (x) = \frac{2 x - 5}{3}

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Question Text	If $f (x) = x + 7$ and $g (x) = x - 7$ , $x \in R$ , find $(f o g) (7)$ . function $f : R \to R$ defined by $f (x) = \frac{3 x + 5}{2}$ is an invertible function, find $f^{- 1}$
Answer Type	Text solution:1
Upvotes	150