If f(x)=2tan−1x+sin−1(1+x22x) then for x>1, f(x)=

Name: Video solution 1: If f(x)=2tan−1x+sin−1(1+x22x) then for x>1, f(x)=
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Description: Video solution 1: If f(x)=2tan−1x+sin−1(1+x22x) then for x>1, f(x)=

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If f(x)=2tan^{-1}x+sin^{-1} ( {2x}{1+x^2} ) then for x>1, f(x)

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If $f (x) = 2 t a n^{- 1} x + s i n^{- 1} (\frac{2 x}{1 + x ^{2}})$ then for x>1, f(x)=

se c^{- 1} x

s i n^{- 1} x

π

\frac{π}{2}

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f (x) = 2 t a n^{- 1} x + s i n^{- 1} (\frac{2 x}{1 + x ^{2}})

then for x>1, f(x)=

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Question Text	If $f (x) = 2 t a n^{- 1} x + s i n^{- 1} (\frac{2 x}{1 + x ^{2}})$ then for x>1, f(x)=
Answer Type	Video solution: 1
Upvotes	150

If f(x)=2tan−1x+sin−1(1+x22x​) then for x>1, f(x)=

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If $f (x) = 2 t a n^{- 1} x + s i n^{- 1} (\frac{2 x}{1 + x ^{2}})$ then for x>1, f(x)=