If $$f:R\rightarrow R$$ and $$g:R\rightarrow R$$ are defined by $$f\left( x \right) =x-\left[ x \right]$$ and $$ g\left( x \right) =\left[ x \right]$$ for $$x\in R$$,where $$[x]$$ is the greatest integer not exceeding $$x$$,then for every $$x\in R$$,$$f(g(x))$$ is equal to

$$x$$

$$0$$

$$f(x)$$

$$g(x)$$

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If $$f:R\rightarrow R$$ and $$g:R\rightarrow R$$ are defined by $$f\left( x \right) =x-\left[ x \right]$$ and $$ g\left( x \right) =\left[ x \right]$$ for $$x\in R$$,where $$[x]$$ is the greatest integer not exceeding $$x$$,then for every $$x\in R$$,$$f(g(x))$$ is equal to

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Text solutionVerified

$$f(g(x))=[x]-[x]$$
As $$[[x]]=[x]$$
$$fog(x)=[x]-[x]=0$$

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Question Text	If $$f:R\rightarrow R$$ and $$g:R\rightarrow R$$ are defined by $$f\left( x \right) =x-\left[ x \right]$$ and $$ g\left( x \right) =\left[ x \right]$$ for $$x\in R$$,where $$[x]$$ is the greatest integer not exceeding $$x$$,then for every $$x\in R$$,$$f(g(x))$$ is equal to
Answer Type	Text solution:1
Upvotes	150

If $$f:R\rightarrow R$$ and $$g:R\rightarrow R$$ are defined by $$f\left( x \right) =x-\left[ x \right]$$ and $$ g\left( x \right) =\left[ x \right]$$ for $$x\in R$$,where $$[x]$$ is the greatest integer not exceeding $$x$$,then for every $$x\in R$$,$$f(g(x))$$ is equal to

Text solutionVerified

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