If f(n)=6n−44n+3, n=32 show that f[f(n)]=n

Given, f(n)=6n−44n+3f[f(n)]=6(6n−44n+3)−44(6n−44n+3)+3=24n+18−24n+1616n+12+18n−12=3434n=n

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If f(n) ={4n+3}{6n-4}, n {2}{3} show that f[f(n)]=n

Question

If $f (n) = \frac{4 n + 3}{6 n - 4}, n \neq = \frac{2}{3}$ show that $f [f (n)] = n$

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Oliver Discussed

f (n) = \frac{4 n + 3}{6 n - 4}, n \neq = \frac{2}{3}

show that

f [f (n)] = n

11 mins ago

Discuss this question LIVE

11 mins ago

Given,

f (n) = \frac{4 n + 3}{6 n - 4}

f [f (n)] = \frac{4 ( \frac{4 n + 3}{6 n - 4} ) + 3}{6 ( \frac{4 n + 3}{6 n - 4} ) - 4}

= \frac{16 n + 12 + 18 n - 12}{24 n + 18 - 24 n + 16}

= \frac{34 n}{34} = n

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Question Text	If $f (n) = \frac{4 n + 3}{6 n - 4}, n \neq = \frac{2}{3}$ show that $f [f (n)] = n$
Answer Type	Text solution:1
Upvotes	150