If f=(132234455166)∈S6. then f−1 is

Given f=(132234455166)∈S6.We have to find f−1.That is, we need to find inverse permutation.From f we see that, 1→3→4→5→1. Therefore in f−1,1→5From f we see that, 2→2. Therefore in f−1,2→2From f we see that, 3→4→5→1→3. Therefore in f−1,3→1From f we see that, 4→5→1→3→4. Therefore in f−1,4→3From f we see that, 5→1→3→4→5. Therefore in f−1,5→4From f we see that, 6→6. Therefore in f−1,6→6Thus f−1=(152231435466).

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If f={pmatrix}1&2&3&4&5&6& 3&2&4&5&1&6{pmatrix} S_6. then f^{

Question

If $f = (132234455166) \in S_{6}$ . then $f^{- 1}$ is

(122531435466)

(152231435466)

(142231435566)

(132231455466)

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Sebastian Discussed

f = (132234455166) \in S_{6}

. then

f^{- 1}

13 mins ago

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13 mins ago

Text solutionVerified

Given

f = (132234455166) \in S_{6}

We have to find

f^{- 1}

That is, we need to find inverse permutation.

From $f$ we see that, $1 \to 3 \to 4 \to 5 \to 1$ . Therefore in $f^{- 1}, 1 \to 5$
From $f$ we see that, $2 \to 2$ . Therefore in $f^{- 1}, 2 \to 2$
From $f$ we see that, $3 \to 4 \to 5 \to 1 \to 3$ . Therefore in $f^{- 1}, 3 \to 1$
From $f$ we see that, $4 \to 5 \to 1 \to 3 \to 4$ . Therefore in $f^{- 1}, 4 \to 3$
From $f$ we see that, $5 \to 1 \to 3 \to 4 \to 5$ . Therefore in $f^{- 1}, 5 \to 4$
From $f$ we see that, $6 \to 6$ . Therefore in $f^{- 1}, 6 \to 6$