If θ=411π, find the value of sin2θ−cos2θ+2tanθ−sec2θ

θ=411π=(3π−4π)sinθ=sin(3π−4π)=sin4π=sin450=21cosθ=cos(3π−4π)=−cos4π=−cos450=−21tanθ=tan(3π−4π)=−tan4π=−tan450=−1∴ Given expression =21−21−2−2=−4

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If ={11 }{4}, find the value of ^{2} - ^{2} +2 - ^{2}

Question

If $θ = \frac{11 π}{4}$ , find the value of $sin^{2} θ - cos^{2} θ + 2 tan θ - sec^{2} θ$

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Alexander Discussed

θ = \frac{11 π}{4}

, find the value of

sin^{2} θ - cos^{2} θ + 2 tan θ - sec^{2} θ

12 mins ago

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12 mins ago

θ = \frac{11 π}{4} = (3 π - \frac{π}{4})

sin θ = sin (3 π - \frac{π}{4}) = sin \frac{π}{4} = sin 4 5^{0} = \frac{1}{2}

cos θ = cos (3 π - \frac{π}{4}) = - cos \frac{π}{4}

= - cos 4 5^{0} = - \frac{1}{2}

tan θ = tan (3 π - \frac{π}{4}) = - tan \frac{π}{4} = - tan 4 5^{0} = - 1

∴

Given expression

= \frac{1}{2} - \frac{1}{2} - 2 - 2 = - 4

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Question Text	If $θ = \frac{11 π}{4}$ , find the value of $sin^{2} θ - cos^{2} θ + 2 tan θ - sec^{2} θ$
Answer Type	Text solution:1
Upvotes	150