If Δ=∣∣11111+x1111+y∣∣ for x=0,y=0, then Δ is

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If ={vmatrix} 1 & 1 & 1 1 & 1+x & 1 1 & 1 & 1+y {vmatrix} f

Question

If $Δ = ∣ ∣ 111 1 1 + x 1 11 1 + y ∣ ∣$ for $x \neq = 0, y \neq = 0$ , then $Δ$ is

divisible by neither

x

nor

y

divisible by both

x

and

y

divisible by

x

but not

y

divisible by

y

but not

x

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Jack Discussed

Δ = ∣ ∣ 111 1 1 + x 1 11 1 + y ∣ ∣

for

x \neq = 0, y \neq = 0

, then

Δ

6 mins ago

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ANSWER IS B

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