If D=∣11111+x1111+y∣f o rx=0,y=0then D is

Option (B)divisible by both x and y

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If {D}={|{1}{1}{1}{1}{1}+{x}{1}{1}{1}{1}+{y}|}{f o r}{x}{0},{y

Question

If $D = ∣ 11111 + x 1111 + y ∣ f o r x \neq = 0, y \neq = 0$ then D is

divisible by neither x nor y

divisible by both x and y

divisible by x but not y

divisible by y but not x

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Mila Discussed

D = ∣ 11111 + x 1111 + y ∣ f o r x \neq = 0, y \neq = 0

then D is

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