If cot−1x+tan−131=2π then x is:

cot−1(x)+tan−1(31)=2π⇒cot−1x=2π−tan−1(31)⇒cot−1x=cot−131On comparing x=31Hence, option (c) is correct.

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If ^{-1}x+^{-1}{1}{3}={}{2} then x is:

Question

If $cot^{- 1} x + tan^{- 1} \frac{1}{3} = \frac{π}{2}$ then $x$ is:

1

3

\frac{1}{3}

none of these

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Amelia Discussed

cot^{- 1} x + tan^{- 1} \frac{1}{3} = \frac{π}{2}

then

x

is:

8 mins ago

Discuss this question LIVE

8 mins ago

cot^{- 1} (x) + tan^{- 1} (\frac{1}{3}) = \frac{π}{2}

\Rightarrow cot^{- 1} x = \frac{π}{2} - tan^{- 1} (\frac{1}{3})

\Rightarrow cot^{- 1} x = cot^{- 1} \frac{1}{3}

On comparing

x = \frac{1}{3}

Hence, option

(c)

is correct.

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Question Text	If $cot^{- 1} x + tan^{- 1} \frac{1}{3} = \frac{π}{2}$ then $x$ is:
Answer Type	Text solution:1
Upvotes	151