If $(b + c - a) / a, (c + a - b) / b, (a + b - c) / c$ are in A.P., then prove that $1 / a, 1 / b, 1 / c$ are also in A.P.

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(b + c - a) / a, (c + a - b) / b, (a + b - c) / c

are in A.P., then prove that

1 / a, 1 / b, 1 / c

are also in A.P.

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Question Text

(b + c - a) / a, (c + a - b) / b, (a + b - c) / c

are in A.P., then prove that

1 / a, 1 / b, 1 / c

are also in A.P.

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