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If $α = \int_{0}^{1} (e^{9} x + 3 tan^{(- 1) x}) (\frac{12 + 9 x ^{2}}{1 + x ^{2}}) d x w h e r η n^{- 1}$ takes only principal values, then the value of $((lo g)_{e} ∣ 1 + α ∣ - \frac{3 π}{4}) i s$

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α = \int_{0}^{1} (e^{9} x + 3 tan^{(- 1) x}) (\frac{12 + 9 x ^{2}}{1 + x ^{2}}) d x w h e r η n^{- 1}

takes only principal values, then the value of

((lo g)_{e} ∣ 1 + α ∣ - \frac{3 π}{4}) i s

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Question Text	If $α = \int_{0}^{1} (e^{9} x + 3 tan^{(- 1) x}) (\frac{12 + 9 x ^{2}}{1 + x ^{2}}) d x w h e r η n^{- 1}$ takes only principal values, then the value of $((lo g)_{e} ∣ 1 + α ∣ - \frac{3 π}{4}) i s$
Answer Type	Video solution: 1
Upvotes	150