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If A=[ {matrix} 1 & 2 & 3 2 & 3 & 2 1 & 2 & 2 {matrix} ] , t

Question

If $A = ⎣ ⎡ 121232322 ⎦ ⎤$ , then

A_{12} + A_{22} + A_{32} = 7

A_{13} + A_{23} + A_{33} = 7

A_{11} + A_{21} = A_{32}

A_{11} + A_{21} \neq = A_{32}

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Eleanor Discussed

A = ⎣ ⎡ 121232322 ⎦ ⎤

, then

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Text solutionVerified

A = ⎣ ⎡ 121232322 ⎦ ⎤

≃

A = ⎣ ⎡ A_{11} A_{21} A_{31} A_{12} A_{22} A_{32} A_{13} A_{23} A_{33} ⎦ ⎤

A_{12} + A_{22} + A_{32} = 2 + 3 + 2 = 7

A_{13} + A_{23} + A_{33} = 3 + 2 + 2 = 7

A_{11} + A_{21} = 1 + 2 = 3

A_{32} = 2

A_{11} + A_{21} \neq = A_{32}

Option A,B D are correct.

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