If A=[a+ib−c+idc+ida−ib] and a2+b2+c2+d2=1, then A−1 is equal to
Assertion :Points P(−sin(β−α),−cosβ),Q(cos(β−α),sinβ) and R(cos(β−α+θ),sin(β−θ)), where β=4π+2α are non-collinear.
Reason :Three given points are non-collinear if they form a triangle of non-zero area.
Find The equation of line passing through the two points (3,1) and (9,3) using determinant, also find the area of triangle if third point is (−2,−4)
The centre of a circle is (−6,4). If one end of the diameter of the circle is at (−12,8), then the other end is at
If the lines L1:λ2x−y−1=0 L2:x−λ2y+1=0 L3:x+y−λ2=0 pass through the same point the value(s) of λ equals