If $A = [2 - 3 22], B = [01 - 1 0]$ then $(B^{- 1} A^{- 1})^{- 1} =$ _______.

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A = [2 - 3 22], B = [01 - 1 0]

then

(B^{- 1} A^{- 1})^{- 1} =

_______.

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\begin{array}{l} A=\left[ { \begin{array} { *{ 20 }{ c } }2 & 2 \\ { -3 } & 2 \end{array} } \right] B=\left[ { \begin{array} { *{ 20 }{ c } }0 & { -1 } \\ 1 & 0 \end{array} } \right] \\ { \left( { { B^{ -1 } }{ A^{ -1 } } } \right) ^{ -1 } }={ \left( { { { \left( { AB } \right) }^{ -1 } } } \right) ^{ -1 } }=AB \\ AB=\left[ { \begin{array} { *{ 20 }{ c } }2 & 2 \\ { -3 } & 2 \end{array} } \right] \left[ { \begin{array} { *{ 20 }{ c } }0 & { -1 } \\ 1 & 0 \end{array} } \right] \\ AB=\left[ { \begin{array} { *{ 20 }{ c } }2 & { -2 } \\ 2 & 3 \end{array} } \right] \end{array}

Hence, this is the answer.

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