If a>0,b>0 then (lim)n→∞(aa−1+bn1)n= b1/a b. ab1 c. ab d. ba

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If {a}>{0},{b}>{0} then {()}_{{{n}}}{({{{a}-{1}+{b}^{{{{1}}{{n

Question

If $a > 0, b > 0$ then $(lim)_{n \to \infty} (\frac{a - 1 + b ^{\frac{1}{n}}}{a})^{n} =$ $b^{1 / a}$ b. $a^{\frac{1}{b}}$ c. $a^{b}$ d. $b^{a}$

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Oliver Discussed

a > 0, b > 0

then

(lim)_{n \to \infty} (\frac{a - 1 + b ^{\frac{1}{n}}}{a})^{n} =

b^{1 / a}

a^{\frac{1}{b}}

a^{b}

b^{a}

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Question Text

a > 0, b > 0

then

(lim)_{n \to \infty} (\frac{a - 1 + b ^{\frac{1}{n}}}{a})^{n} =

b^{1 / a}

a^{\frac{1}{b}}

a^{b}

b^{a}