If 3x=secθ and x3=tanθ, then find the value of 9(x2−x21 )

sec2θ−tan2θ=1(3x)2−(x3)2=19x2−x29=19(x2−x21)=1

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If 3x=sec and { 3 }{ x } =tan , then find the value of 9( { x

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If 3x=sec $θ$ and $\frac{3}{x} = t an θ,$ then find the value of 9 $(x^{2} - \frac{1}{x ^{2}})$

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Charlotte Discussed

If 3x=sec

θ

and

\frac{3}{x} = t an θ,

then find the value of 9

(x^{2} - \frac{1}{x ^{2}})

12 mins ago

Discuss this question LIVE

12 mins ago

sec^{2} θ - tan^{2} θ = 1

(3 x)^{2} - (\frac{3}{x})^{2} = 1

9 x^{2} - \frac{9}{x ^{2}} = 1

9 (x^{2} - \frac{1}{x ^{2}}) = 1

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Question Text	If 3x=sec $θ$ and $\frac{3}{x} = t an θ,$ then find the value of 9 $(x^{2} - \frac{1}{x ^{2}})$
Answer Type	Text solution:1
Upvotes	151