If (2+sinx)dxdy+(y+1)cosx=0and y(0)=1,theny(2π)is equal to −31 (2) 34 (3) 31 (4) −32

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Question

If $(2 + sin x) \frac{d y}{d x} + (y + 1) cos x = 0$ and $y (0) = 1, t h e n y (\frac{π}{2})$ is equal to $- \frac{1}{3}$ (2) $\frac{4}{3}$ (3) $\frac{1}{3}$ (4) $- \frac{2}{3}$

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(2 + sin x) \frac{d y}{d x} + (y + 1) cos x = 0

and

y (0) = 1, t h e n y (\frac{π}{2})

is equal to

- \frac{1}{3}

(2)

\frac{4}{3}

(3)

\frac{1}{3}

(4)

- \frac{2}{3}

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Question Text

(2 + sin x) \frac{d y}{d x} + (y + 1) cos x = 0

and

y (0) = 1, t h e n y (\frac{π}{2})

is equal to

- \frac{1}{3}

(2)

\frac{4}{3}

(3)

\frac{1}{3}

(4)

- \frac{2}{3}