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How many numbers lying between 100 and 1000 can be formed with the digits 0, 1, 2, 3, 4, 5, if the repetition of the digits is not allowed?
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The numbers lying between & are digit numbers .We are to form digit numbers between & such that there's no repitition.
We have six different digits to be filled in three vacant places.
Since we have to form three digit number
cannot be in the hunderdth place .
So the place can be filled in ways .
Now having filled the place,we are left with numbers for the place i.e., place can be filled in ways.
And the one's place can be filled with different numbers .
By the fundamental principle of counting, the required number of numbers lying between & formed out of .
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| Question Text | How many numbers lying between 100 and 1000 can be formed with the digits 0, 1, 2, 3, 4, 5, if the repetition of the digits is not allowed? |
| Answer Type | Text solution:1 |
| Upvotes | 152 |
