Question
How many numbers exceeding and not exceeding can be formed, such that each digit is any of the first six whole numbers?
Found 4 tutors discussing this question
Discuss this question LIVE
13 mins ago
Text solutionVerified
We need to find digit numbers less than equal to which contain only
The first digit (thousands digit) cannot be or since would make it a digit number not since number
digit can be any of the other
The can be any of the whole numbers.
Total
Also including it is
Hence, the answer is
Was this solution helpful?
150
Share
Report
One destination to cover all your homework and assignment needs
Learn Practice Revision Succeed
Instant 1:1 help, 24x7
60, 000+ Expert tutors
Textbook solutions
Big idea maths, McGraw-Hill Education etc
Essay review
Get expert feedback on your essay
Schedule classes
High dosage tutoring from Dedicated 3 experts
Practice questions from similar books
Question 1
There are 3 copies each of 4 different books. In how many ways can they be arranged in a shelf?Question 2
The minimum marks required for clearing a certain screening paper is 210 out of 300. The screening paper consists of 3 sections each of Physics, Chemistry and Maths. Each section has 100 as maximum marks. Assuming there is no negative marking and marks obtained in each section are integers, the no. of ways in which a student can qualify the exam is(Assuming no cut off limit).Stuck on the question or explanation?
Connect with our maths tutors online and get step by step solution of this question.
231 students are taking LIVE classes
Question Text | How many numbers exceeding and not exceeding can be formed, such that each digit is any of the first six whole numbers? |
Answer Type | Text solution:1 |
Upvotes | 150 |