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How many numbers each lying between 9 and 1000 can be formed w

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How many numbers each lying between $9$ and $1000$ can be formed with the digits $0, 1, 2, 3, 7, 8$ if repetition of the digits in a number is allowed?

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Sophia Discussed

How many numbers each lying between

9

and

1000

can be formed with the digits

0, 1, 2, 3, 7, 8

if repetition of the digits in a number is allowed?

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

0, 1, 2, 3, 7, 8

Repetition is allowed

Two digit number:

First digit has

5

Ways

(1, 2, 3, 7, 8)

Second digit has

6

Ways

(0, 1, 2, 3, 7, 8)

Number of possible two digit number is

30

Three digit number:

First digit has

5

Ways

(1, 2, 3, 7, 8)

Second digit has

6

Ways

(0, 1, 2, 3, 7, 8)

Third digit has

6

Ways

(0, 1, 2, 3, 7, 8)

Number of possible three digit number is

180

Total number possible from

9

1000

= 180 + 30

= 210

Numbers

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Question Text	How many numbers each lying between $9$ and $1000$ can be formed with the digits $0, 1, 2, 3, 7, 8$ if repetition of the digits in a number is allowed?
Answer Type	Text solution:1
Upvotes	150

How many numbers each lying between 9 and 1000 can be formed with the digits 0,1,2,3,7,8 if repetition of the digits in a number is allowed?

Text solutionVerified

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How many numbers each lying between $9$ and $1000$ can be formed with the digits $0, 1, 2, 3, 7, 8$ if repetition of the digits in a number is allowed?