Class 11

Math

Co-ordinate Geometry

Straight Lines

How many number greater than a million can be formed with the digits $2,3,0,7,7,3,7,?$

**Here**

**One
million $=10,00,000.$ given numbers are $2,3,0,7,7,3,7$**

**A
number greater than $1000000$ has $7$
places, and all the digits are to be
used. But $7$ is repeated thrice and $3$ is repeated twice.**

**Total
number of ways arranging $7$ digits$=2!×3!7! =2×1×3!7×6×5×4×3! =420$**

**But
the numbers begin with $0$ are no more $7$ digits numbers then reject those
numbers.**

**Therefore,
these can be arranged in $2!×3!6! =60$**

**Then
required number arrangements$=420−60=360$**