Class 11

Math

Algebra

Permutations and Combinations

How many different words can be formed using all the letters of the word $_{′}ALLAHABAD_{′}$ when both $L_{′}s$ are not together

- $4200$
- $5812$
- $6000$
- $5250$

Total number of words $=4!×2!9! =7560$

Concider both L's as $1$ identity

Number of such words $=4!8! ×2=3360$ Ways

Number of words in which L's are not together

=Total number of words $−$ Words with $L$ are together

$=7560−3360$

$=4200$

Therefore number of possiblities $=4200$