For three events A,Band C,P(Exactly one of Aor Boccurs) =P(Exactly one of Bor Coccurs) =P(Exactly one of Cor Aoccurs) =41and P(All the three events occur simultaneously) =61˙Then the probability that at least one of the events occurs, is : 647 (2) 163 (3) 327 (4) 167

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For three events {A},{B}and {C},{P}(Exactly one of {A}or {B}oc

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For three events $A, B$ and $C, P$ (Exactly one of $A$ or $B$ occurs) $= P$ (Exactly one of $B$ or $C$ occurs) $= P$ (Exactly one of $C$ or $A$ occurs) $= \frac{1}{4}$ and $P$ (All the three events occur simultaneously) $= \frac{1}{6} ˙$ Then the probability that at least one of the events occurs, is : $\frac{7}{64}$ (2) $\frac{3}{16}$ (3) $\frac{7}{32}$ (4) $\frac{7}{16}$

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For three events

A, B

and

C, P

(Exactly one of

A

B

occurs)

= P

(Exactly one of

B

C

occurs)

= P

(Exactly one of

C

A

occurs)

= \frac{1}{4}

and

P

(All the three events occur simultaneously)

= \frac{1}{6} ˙

Then the probability that at least one of the events occurs, is :

\frac{7}{64}

(2)

\frac{3}{16}

(3)

\frac{7}{32}

(4)

\frac{7}{16}

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Question Text

For three events

A, B

and

C, P

(Exactly one of

A

B

occurs)

= P

(Exactly one of

B

C

occurs)

= P

(Exactly one of

C

A

occurs)

= \frac{1}{4}

and

P

(All the three events occur simultaneously)

= \frac{1}{6} ˙

Then the probability that at least one of the events occurs, is :

\frac{7}{64}

(2)

\frac{3}{16}

(3)

\frac{7}{32}

(4)

\frac{7}{16}

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Practice questions from similar books

For three events A,Band C,P(Exactly one of Aor Boccurs) =P(Exactly one of Bor Coccurs) =P(Exactly one of Cor Aoccurs) =41​and P(All the three events occur simultaneously) =61​˙Then the probability that at least one of the events occurs, is : 647​ (2) 163​ (3) 327​ (4) 167​

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