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Five - digit numbers divisible by 3 are formed using 0, 1, 2,

Question

Five - digit numbers divisible by 3 are formed using 0, 1, 2, 3, 4, 5 without repetition. The total number of such numbers is :

312

3125

120

216

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Five - digit numbers divisible by 3 are formed using 0, 1, 2, 3, 4, 5 without repetition. The total number of such numbers is :

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Text solutionVerified

Numbers using

1, 2, 3, 4, 5 (1 + 2 + 3 + 4 + 5 = 15)

\Rightarrow

The number of choices we have

= 5! = 120

Numbers using

0, 1, 2, 4, 5 (0 + 1 + 2 + 4 + 5 = 12)

\Rightarrow

The number of choices we have

= 5! - 4!

= 120 - 24

= 96

There are

4!

numbers beginning with

0

∴

Total number of numbers

= 120 + 96 = 216

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Question Text	Five - digit numbers divisible by 3 are formed using 0, 1, 2, 3, 4, 5 without repetition. The total number of such numbers is :
Answer Type	Text solution:1
Upvotes	150