Find the vector equation of line passing through the point $(1, 2, - 4)$ and perpendicular to the two lines: $\frac{x - 8}{3} = \frac{y + 19}{- 16} = \frac{z - 10}{7} a n d \frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}$

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Find the vector equation of line passing through the point

(1, 2, - 4)

and perpendicular to the two lines:

\frac{x - 8}{3} = \frac{y + 19}{- 16} = \frac{z - 10}{7} a n d \frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}

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Question Text

Find the vector equation of line passing through the point

(1, 2, - 4)

and perpendicular to the two lines:

\frac{x - 8}{3} = \frac{y + 19}{- 16} = \frac{z - 10}{7} a n d \frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}

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