Find the values of the following:tan−1{2cos(2sin−121)}.

tan−1{2cos(2sin−121)}=tan−1{2cos(2×6π)}=tan−1{2cos(3π)}=tan−1{2×21}=tan−1{1}=4π

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Find the values of the following: ^{-1} {2 (2^{-1} {1}{2} )

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Find the values of the following:
$tan^{- 1} {2 cos (2 sin^{- 1} \frac{1}{2})}$ .

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Evelyn Discussed

Find the values of the following:

tan^{- 1} {2 cos (2 sin^{- 1} \frac{1}{2})}

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11 mins ago

tan^{- 1} {2 cos (2 sin^{- 1} \frac{1}{2})}

= tan^{- 1} {2 cos (2 \times \frac{π}{6})}

= tan^{- 1} {2 cos (\frac{π}{3})}

= tan^{- 1} {2 \times \frac{1}{2}}

= tan^{- 1} {1}

= \frac{π}{4}

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Question Text	Find the values of the following: $tan^{- 1} {2 cos (2 sin^{- 1} \frac{1}{2})}$ .
Answer Type	Text solution:1
Upvotes	150