Find the value of sin2θ if sinθ=5−3 and π<θ<32π

Given that θ lies in Q3 So, 2π<θ<3πGiven that sinθ=5−3Therefore, cosθ=54⇒sin2θ=2sinθcosθ⇒sin2θ=2(5−3)(5−4)⇒sin2θ=2524

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Find the value of {2} if {}={-3}{5} and < < 3{}{2}

Question

Find the value of $sin 2 θ$ if $sin θ = \frac{- 3}{5}$ and $π < θ < 3 \frac{π}{2}$

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Levi Discussed

Find the value of

sin 2 θ

sin θ = \frac{- 3}{5}

and

π < θ < 3 \frac{π}{2}

11 mins ago

Discuss this question LIVE

11 mins ago

Given that

θ

lies in

Q_{3}

So,

2 π < θ < 3 π

Given that

sin θ = \frac{- 3}{5}

Therefore,

cos θ = \frac{4}{5}

\Rightarrow sin 2 θ = 2 sin θ cos θ

\Rightarrow sin 2 θ = 2 (\frac{- 3}{5}) (\frac{- 4}{5})

\Rightarrow sin 2 θ = \frac{24}{25}

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Question Text	Find the value of $sin 2 θ$ if $sin θ = \frac{- 3}{5}$ and $π < θ < 3 \frac{π}{2}$
Answer Type	Text solution:1
Upvotes	150