Find the shortest distance between the following lines: 7x+1=−6y+1=1z+1;−13−x=−2y−5=1z−7

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Question

Find the shortest distance between the following lines: $\frac{x + 1}{7} = \frac{y + 1}{- 6} = \frac{z + 1}{1}; \frac{3 - x}{- 1} = \frac{y - 5}{- 2} = \frac{z - 7}{1}$

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Find the shortest distance between the following lines:

\frac{x + 1}{7} = \frac{y + 1}{- 6} = \frac{z + 1}{1}; \frac{3 - x}{- 1} = \frac{y - 5}{- 2} = \frac{z - 7}{1}

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Question Text

Find the shortest distance between the following lines:

\frac{x + 1}{7} = \frac{y + 1}{- 6} = \frac{z + 1}{1}; \frac{3 - x}{- 1} = \frac{y - 5}{- 2} = \frac{z - 7}{1}