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Find the inverse of the matrix- [ {{array}{*{20}{c}}3&{ - 2}{

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Find the inverse of the matrix-
\left[ {\begin{array}{*{20}{c}}3&{ - 2}\\{ - 1}&1\end{array}} \right]

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Text solutionVerified

Let A=\left[ {\begin{array}{*{20}{c}}3&{ - 2}\\{ - 1}&1\end{array}} \right]

Inverse of matrix is given as

A^{- 1} = \frac{A d j A}{De t A}

Adj

A =

[1123]

∣ A ∣ = 3 (1) - (- 2) (- 1) = 3 - 2 = 1

So Inverse of matrix is

A^{- 1} = \frac{[ 1 1 2 3 ]}{1} = [1123]

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Question Text	Find the inverse of the matrix- \left[ {\begin{array}{*{20}{c}}3&{ - 2}\\{ - 1}&1\end{array}} \right]
Answer Type	Text solution:1
Upvotes	150