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Find the first three terms of the A.P. whose first term is 2/3 and common difference is 1/3?
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Let the series be $$a_1, a_2, a_3, a_4, ......$$
$$a_1 = a = 2/3$$
Common difference = 1/3
$$a_2 = a_1 + d = 2/3 + 1/3 = 1$$
$$a_3 = a_2 + d = 1 + 1/3 = 4/3$$
$$a_4 = a_3 + d = 4/3 + 1/3 = 5/3$$
Therefore, first three terms of this A.P. will be 1/3, 1,4/3, 5/3, ......
$$a_1 = a = 2/3$$
Common difference = 1/3
$$a_2 = a_1 + d = 2/3 + 1/3 = 1$$
$$a_3 = a_2 + d = 1 + 1/3 = 4/3$$
$$a_4 = a_3 + d = 4/3 + 1/3 = 5/3$$
Therefore, first three terms of this A.P. will be 1/3, 1,4/3, 5/3, ......
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| Question Text | Find the first three terms of the A.P. whose first term is 2/3 and common difference is 1/3? |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
