Find the equation of the plane containing the lines 4x−5=4y−7=−5z+3and7x−8=1y−4=3z−5˙

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Find the equation of the plane containing the lines {{{x}-{5}}

Question

Find the equation of the plane containing the lines $\frac{x - 5}{4} = \frac{y - 7}{4} = \frac{z + 3}{- 5} a n d \frac{x - 8}{7} = \frac{y - 4}{1} = \frac{z - 5}{3} ˙$

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Find the equation of the plane containing the lines

\frac{x - 5}{4} = \frac{y - 7}{4} = \frac{z + 3}{- 5} a n d \frac{x - 8}{7} = \frac{y - 4}{1} = \frac{z - 5}{3} ˙

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Question Text

Find the equation of the plane containing the lines

\frac{x - 5}{4} = \frac{y - 7}{4} = \frac{z + 3}{- 5} a n d \frac{x - 8}{7} = \frac{y - 4}{1} = \frac{z - 5}{3} ˙