Find the equation of the circle whose radius is 3 and which touches internally the circle $x^{2} + y^{2} - 4 x - 6 y = - 12 = 0$ at the point $(- 1, - 1) ˙$

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Find the equation of the circle whose radius is 3 and which touches internally the circle

x^{2} + y^{2} - 4 x - 6 y = - 12 = 0

at the point

(- 1, - 1) ˙

14 mins ago

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Question Text

Find the equation of the circle whose radius is 3 and which touches internally the circle

x^{2} + y^{2} - 4 x - 6 y = - 12 = 0

at the point

(- 1, - 1) ˙

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