Find the equation of line through $(- 4, 1, 3)$ & parallel to the plane $x + y + z = 3$ while the line intersects another line whose eqution is $x + y - z = x + 2 y - 3 z + 5$ (a) \displaystyle\frac{{{x}+{4}}}{{-{3}}}=\frac{{{y}-{1}}}{{-{2}}}=\frac{{{z}-{3}}}{}

(b)

(x+4)/(1)=(y-1)/

=(z-3)/(-3)

(c)

(x+4)/(-3)=(y-1)/(2)=(z-3)/(1)\displaystyle{\left({d}\right)}

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Olivia Discussed

Find the equation of line through

(- 4, 1, 3)

& parallel to the plane

x + y + z = 3

while the line intersects another line whose eqution is

x + y - z = x + 2 y - 3 z + 5

(a) \displaystyle\frac{{{x}+{4}}}{{-{3}}}=\frac{{{y}-{1}}}{{-{2}}}=\frac{{{z}-{3}}}{}

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Question Text

Find the equation of line through

(- 4, 1, 3)

& parallel to the plane

x + y + z = 3

while the line intersects another line whose eqution is

x + y - z = x + 2 y - 3 z + 5

(a) \displaystyle\frac{{{x}+{4}}}{{-{3}}}=\frac{{{y}-{1}}}{{-{2}}}=\frac{{{z}-{3}}}{}

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