Find the distance between the line −3x+1=2y−3=1z−2 and the plane x+y+z+3=0.

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Find the distance between the line {{{x}+{1}}}{{-{3}}}={{{y}-{

Question

Find the distance between the line $\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z - 2}{1}$ and the plane $x + y + z + 3 = 0 .$

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Mateo Discussed

Find the distance between the line

\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z - 2}{1}

and the plane

x + y + z + 3 = 0 .

7 mins ago

Discuss this question LIVE

7 mins ago

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Question Text

Find the distance between the line

\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z - 2}{1}

and the plane

x + y + z + 3 = 0 .