Find the 11th term from the end in the expansion of (2x−x21)25

(2x−x21)25Total terms = 2611th term from last = 16th term from start.⇒n=15tn+1=mCn.am−nbn in (a+b)m∴t16=26C15(2n)11(x2−1)15=−26C15×211×x30x11=−26C15×211×x−19

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Home

Find the 11th term from the end in the expansion of ( 2x - {1

Question

Find the 11th term from the end in the expansion of $(2 x - \frac{1}{x ^{2}})^{25}$

^{25} C_{10} (\frac{2 ^{15}}{x ^{5}}), -^{25} C_{15} (\frac{2 ^{10}}{x ^{20}})

Views: 607 students

Found 7 tutors discussing this question

Daniel Discussed

Find the 11th term from the end in the expansion of

(2 x - \frac{1}{x ^{2}})^{25}

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

(2 x - \frac{1}{x ^{2}})^{25}

Total terms = 26

1 1^{t h}

term from last =

1 6^{t h}

term from start.

\Rightarrow n = 15

t_{n + 1} =^{m} C_{n} . a^{m - n} b^{n}

(a + b)^{m}

∴ t_{16} =^{26} C_{15} (2 n)^{11} (\frac{- 1}{x ^{2}})^{15}

= -^{26} C_{15} \times 2^{11} \times \frac{x ^{11}}{x ^{30}}

= -^{26} C_{15} \times 2^{11} \times x^{- 19}

Was this solution helpful?

150

Report

One destination for complete JEE/NEET preparation

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Find the 11th term from the end in the expansion of $(2 x - \frac{1}{x ^{2}})^{25}$
Answer Type	Text solution:1
Upvotes	150

Find the 11th term from the end in the expansion of (2x−x21​)25

Text solutionVerified

Practice questions from similar books

Find the 11th term from the end in the expansion of $(2 x - \frac{1}{x ^{2}})^{25}$