Find dxdy at x=1, y=4π if sin2y+cosxy=k

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Find {{{.{d}{y}.}}}{{{.{d}{x}.}}} at {x}={1}, {y}={}{{4}} if {

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Find $\frac{d y}{d x}$ at $x = 1$ , $y = \frac{π}{4}$ if $sin^{2} y + cos x y = k$

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Find

\frac{d y}{d x}

x = 1

y = \frac{π}{4}

sin^{2} y + cos x y = k

13 mins ago

Discuss this question LIVE

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Practice questions from similar books

Question 1

If x 1 + y + y 1 + x = 0, prove that \frac{d y}{d x} = - \frac{1}{( x + 1 ) ^{2}} .

View solution

Question 2

Find the derivative of

(sin x)^{x} + sin^{- 1} x

w.r.t.

x

View solution

Question 3

x lo g_{e} (lo g_{e} x) - x^{2} + y^{2} = 4

then

(\frac{d y}{d x})_{a t x = e}

is equal to (A)

\frac{2 e + 1}{4 + e ^{2}}

(B)

\frac{e}{2 4 + e ^{2}}

(C)

\frac{2 e + 1}{2 ( 4 + e ^{2} )}

(D)

\frac{2 e - 1}{2 ( 4 + e ^{2} )}

View solution

Question 4

Repeated roots : If equation f(x) = 0, where f(x) is a polyno- mial function, has roots

α, α, β, \dots or α

root is repreated root, then f(x) = 0 is equivalent to

(x - α)^{2} (x - β) \dots = 0,

from which we can conclude that

f (x) = 0 or 2 (x - α) [(x - β) \dots] + (x - α)^{2} [(x - β) \dots]^{'} = 0 or (x - α) [2 {(x - β) \dots} + (x - α) {(x - β) \dots}^{'}] = 0

has root

α

. Thus, if

α

root occurs twice in the, equation, then it is common in equations f(x) = 0 and f'(x) = 0. Similarly, if

α

root occurs thrice in equation, then it is common in the equations f(x)=0, f'(x)=0, and f'''(x)=0.
If

a_{1} x^{3} + b_{1} x^{2} + c_{1} x + d_{1} = 0 and a_{2} x^{3} + b_{2} x^{2} + c_{2} x + d_{2} = 0

have a pair of repeated roots common, then

∣ ∣ 3 a_{1} 3 a_{2} a_{2} b_{1} - a_{1} b_{2} 2 b_{1} 2 b_{2} c_{1} a_{2} - c_{2} a_{1} c_{1} c_{2} d_{1} a_{2} - d_{2} a_{1} ∣ ∣ =

View solution

Question Text

Find

\frac{d y}{d x}

x = 1

y = \frac{π}{4}

sin^{2} y + cos x y = k

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Find dxdy​ at x=1, y=4π​ if sin2y+cosxy=k

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Practice questions from similar books

Find $\frac{d y}{d x}$ at $x = 1$ , $y = \frac{π}{4}$ if $sin^{2} y + cos x y = k$