Evaluate: sec−1(x−1x+1)+sin−1(x+1x−2)

Solution :-sec−1(x−1x+1)+sin−1(x+1x−1)⇒cos−1(x+1x−1)+sin−1(x+1x−1)⇒2π

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Evaluate: { ^{ - 1}}( {{{x + 1}}{{x - 1}}} ) + { ^{ - 1}}( {{{

Question

Evaluate: $sec^{- 1} (\frac{x + 1}{x - 1}) + sin^{- 1} (\frac{x - 2}{x + 1})$

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Evaluate:

sec^{- 1} (\frac{x + 1}{x - 1}) + sin^{- 1} (\frac{x - 2}{x + 1})

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Solution :-

se c^{- 1} (\frac{x + 1}{x - 1}) + s i n^{- 1} (\frac{x - 1}{x + 1})

\Rightarrow co s^{- 1} (\frac{x - 1}{x + 1}) + s i n^{- 1} (\frac{x - 1}{x + 1})

\Rightarrow \frac{π}{2}

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Question Text	Evaluate: $sec^{- 1} (\frac{x + 1}{x - 1}) + sin^{- 1} (\frac{x - 2}{x + 1})$
Answer Type	Text solution:1
Upvotes	150